The mean number of bumped airline passengers per day s 1.35 and the standard deviation is 0.25. For a random selection of a group of 40 days, what is the probability that the mean number of bumped passengers for the 40 days will be between 1.25 and 1.50?

Answer 1

Z = (score-mean)/SEm

SEm = SD/√n

n = 40

Use same table.