n = 20
µ = 7
σ = 2
(7-2(2), 7+ 2(2)
(µ-2σ, µ + 2σ)
k = 2
1-1/k^2
1- 1/(2)^2
1-1/4
(4-1)/4 = 3/4 = 0.75
at least (20)(.75) = 15 shuttle flights lasted between 3 days and 11 days.
The mean length of the first 20 space shuttle flights was about 7 days with a standard deviation of about 2 days. Using Chebychev's theorem, at least how many of the flights lasted between 3 and 11 days.
1 answer