z = (x-u)/sigma = (25 -24.5)/2.8 = .18
F(.18) from normal table is about .57
the mean age at which men in the united states marry for the first time follows the normal distribution with a mean of 24.5 years. the standard deviation is 2.8 years. for a rabdom sample of 59 men, what is the likelihood that the age they were married were less than 25
2 answers
You're wrong