Asked by Leah
The maximum velocity and acceleration of a particle executing SHM about its equilibrium position are 4.0m/s and 64.0m/ss respectively. If the acceleration of the particle is -64.0m/ss at t=0. Write an expression for the velocity of the particle as a function of time
Answers
Answered by
Alexandra
I cant believe you Leah, do your school work yourself!!
Just so you know it's Jazmine! I'm telling mom!
Just so you know it's Jazmine! I'm telling mom!
Answered by
bobpursley
if displacement = amplitude*cos(wt)=Acos(wt)
then velocity= -Aw*sin(wt)
and acceleration= - Aw^2coswt
Aw^2=64
Aw=4
4w=64 w=16
velocity=-Awsinwt=-4sinwt=-4sin(16t)
check my thinking.
then velocity= -Aw*sin(wt)
and acceleration= - Aw^2coswt
Aw^2=64
Aw=4
4w=64 w=16
velocity=-Awsinwt=-4sinwt=-4sin(16t)
check my thinking.
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