f(x) = -e^x + x
f'(x) = 1 - e^x
so, any max will occur where
e^x = 1
So, sorry, not -1.
The maximum value of f(x) = −ex + x is:
0
–1
1
In 2
Is it -1?
2 answers
sorry. my bad. You are correct. f(0) = -1.