The maximum speed of a child on a swing is 4.90 m/s. The child's height above the ground is 0.525 m at the lowest point in his motion. How high above the ground is he at his highest point?

Answer 1

h₀=0.525 m, v = 4.9 m/s, H=?
mv²/2= mgh
h= v²/2g
H=h+h₀= v₀²/2g + h₀

Answer 2

The above answer is H=21.0675