The maximum load m of a beam varies directly as the breadth b and the square of the depth d and inversely as the length l.If a beam 3.6m long,1.2m wide,and 2.4m deep can safely bear a load up to 909kg,find the maximum safe load for a beam of the same material which is 3m long,6m wide,and 1.8m deep

Answer 1

If the load is called z, then
z = kbd^2/L
Thus, zL/bd^2 = k is constant
So you want to find z such that
(z*3)/(6*1.8^2) = (909*3.6)/(1.2*2.4^2)
z = 3067.88 kg