The math department is making a committee that consists of 4 members there are 9 women and 7 men in the math department, How many different committees can be made if there needs to be 2 men and 2 women

Answer 1

First, we need to calculate the number of ways to choose 2 men from 7 men and 2 women from 9 women.

Number of ways to choose 2 men from 7 men:
7 choose 2 = 7! / (2!(7-2)!) = 21

Number of ways to choose 2 women from 9 women:
9 choose 2 = 9! / (2!(9-2)!) = 36

Now, we find the total number of ways to form the committee by multiplying the number of ways to choose men and women:
Total number of ways = 21 * 36 = 756

Therefore, there are 756 different committees that can be made with 2 men and 2 women from the math department.