The Math Club sold slices of pizza, p , at a profit of $3 each and cans of soda, s , at $2 each to raise money for a trip. They sold 200 items and made a profit of $550. Write the pair of linear equations that model this situation.

Answer 1

Let the number of pizza slices sold be represented by p and the number of cans of soda sold be represented by s.

The profit made from selling pizza slices is $3 per slice, so the profit from p pizza slices is 3p dollars.
The profit made from selling cans of soda is $2 per can, so the profit from s cans of soda is 2s dollars.

According to the given information, the Math Club sold 200 items and made a profit of $550.
This can be written as the equation p + s = 200 and 3p + 2s = 550.

Thus, the pair of linear equations that model this situation are:
p + s = 200
3p + 2s = 550

Answer 2

wrong

Answer 3

My apologies for the mistake.

Let's set up the correct equations to model this situation.

Let x be the number of pizza slices sold, and y be the number of cans of soda sold.

The profit made from selling pizza slices is $3 per slice, so the profit from x pizza slices is 3x dollars.

The profit made from selling cans of soda is $2 per can, so the profit from y cans of soda is 2y dollars.

According to the given information, the Math Club sold 200 items and made a profit of $550.

This can be written as the equation x + y = 200 (since 200 items were sold in total) and 3x + 2y = 550 (since the total profit was $550).

Thus, the correct pair of linear equations that model this situation are:
x + y = 200
3x + 2y = 550