m = ks^6
m/s^6 = k a constant
If m is replaced with 15m, then you want a new s such that
15m/s^6 = m/2^6
s^6 = 15*2^6
s = 2*15^(1/6) = 3.14 mi/hr
The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain river normally flows at a speed of 2 miles per hour. What must its speed be in order to transport particles that are 15 times as massive as usual? Round your answer to the nearest hundredth.
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