The mass of the float is 50.0 kh and it has a volume of 1.0 m^3.det ermine the density of the float and the tension on the rope. You may assume g=10N/kg.

So I know that
mfloat = 50.0kg
weight of float = 50.0 x 10 = 500N
Vfloat = 1.0 m^3
density of Sea water = 1000kg/m^3

D=m/v...50.00kg/1.0m^3 = 50kg/m^3.

then for the tension of the rope I need to calculate the Buoyant force via Archemde's principle ...I get lost right around here can anyone make corrections and show me how it's done?

1 answer

You didn't give all of the INFO.

Density = m/V = 50kg/1m^3 = 50kg/m^3