The marching band is holding a fundraiser. The band is selling t-shirts for $22 and yearbooks for $23. The goal is to sell at least $2,400 in merchandise. Which of the following is a solution to this scenario?

Answer 1

There are multiple solutions to this scenario, but one possible solution is:

Let x be the number of t-shirts sold.
Let y be the number of yearbooks sold.
The total amount of money earned from selling t-shirts is 22x.
The total amount of money earned from selling yearbooks is 23y.
The total amount of merchandise sold is x + y.
According to the problem, the goal is to sell at least $2,400 in merchandise:
22x + 23y ≥ 2400
This is a linear inequality in two variables.
To find a solution, we could use trial and error, or we could graph the inequality and shade the region that satisfies it.

One possible solution is:
x = 90 (sell 90 t-shirts)
y = 70 (sell 70 yearbooks)
Check: 22x + 23y = 1980 + 1610 = 3590 > 2400 (OK)
Therefore, one possible solution to this scenario is to sell 90 t-shirts and 70 yearbooks. The total amount of money earned would be:
22(90) + 23(70) = 1980 + 1610 = 3590.