Isn't there a formula for this?
you know B, and v, and q.
calculate the force moving the proton inward, then set that equal to centripetal force , m v^2/r, calcualte r.
The magnetic field of the Earth at a certain location is directed vertically downward and has a magnitude of 54.0 µT. A proton is moving horizontally towards the west in this field with a speed of 6.00 ✕ 106 m/s
What is the radius of the circular arc followed by this proton?
km
1 answer
1 answer