The loudest sound measured one night during a hockey game was 112 dB. The loudest sound measured during a hockey game the next night was 118 dB. What fraction of sound intensity of the second game was the sound intensity of the first game?

Answer 1

I believe the physics formula for comparisons of sound intensity in decibels is

10^(112/10) / 10^(118/10)
= 10^11.2 / 10^11.8
= 10^-.6
= .2511...
or appr 1/4 of the intensity

Answer 2

0.99