The local reader’s club has a set of 36 hardback books and a set of 30 paperbacks. Each set can be divided equally among the club members. What is the greatest possible number of club members?
23 answers
What is the largest common factor?
idk, uhm 6?
Right. So the greatest number of club members is 6.
thanks!
You're welcome.
if anybody has all the answers please tell me i need to get all of the questions right so i get a good score on the unit 3 math test
please i need the anwers
Ok hey yall im feeling nice so yall are getting the answers...
1. D: 35/30<22/12
2. B: 6^5
3. A: -16
4.D: -1
5.D: 1,012
6.A: 189
7. B: 23
8.A: 9
9.D: 8
10.D: A=1/4, B=7/16,C=5/8,D=3/4
11.D: 46/7
12.C: 3 1/4, 13/4
13. D: A=-0.7,B=-9/16,C=-.4,D=5/16
14.D:Felisha
15.C:4
16.B:4,140
17. C: 3,9
18.A: 13/25
19. A: 4 1/3
20.B: 0.3125
21.D: 31/100
22.B:6
THESE ANSWERS ARE FROM THE CONECSUS LESSON FOR MATH IF ANY ARE WRONG PLS LEMME KNOW :3
1. D: 35/30<22/12
2. B: 6^5
3. A: -16
4.D: -1
5.D: 1,012
6.A: 189
7. B: 23
8.A: 9
9.D: 8
10.D: A=1/4, B=7/16,C=5/8,D=3/4
11.D: 46/7
12.C: 3 1/4, 13/4
13. D: A=-0.7,B=-9/16,C=-.4,D=5/16
14.D:Felisha
15.C:4
16.B:4,140
17. C: 3,9
18.A: 13/25
19. A: 4 1/3
20.B: 0.3125
21.D: 31/100
22.B:6
THESE ANSWERS ARE FROM THE CONECSUS LESSON FOR MATH IF ANY ARE WRONG PLS LEMME KNOW :3
Ms Sue? Can you help?? Plsss
dont mind me just looking
also yes she is wrong
plz help me with my unit test : /
That was so much help yeeeter skeeeeetr
The number of hardback books in a set = 49
The number of paperbacks in a set =21
Since each set can be divided equally among the club members then to find the greatest possible number of club members, we need to find the greatest common factor of 49 and 21.
The prime factorization of 49 and 21 :
49 = 7 x 7
21 = 3 x 7
We can see that the greatest common factor of 49 and 21 =7
Thus, the greatest possible number of club members is 7
The number of paperbacks in a set =21
Since each set can be divided equally among the club members then to find the greatest possible number of club members, we need to find the greatest common factor of 49 and 21.
The prime factorization of 49 and 21 :
49 = 7 x 7
21 = 3 x 7
We can see that the greatest common factor of 49 and 21 =7
Thus, the greatest possible number of club members is 7
oh also GET YO ANSWERS is incorrect don't listen to them
i just realized i put the answer for a different question. oops well if ur question is this then listen to me otherwise don't
The local readers’ club has a set of 49 hardback books and a set of 21 paperbacks. each set can be divided equally among the club members. what is the greatest possible number of club members?14 21 147 7
The local readers’ club has a set of 49 hardback books and a set of 21 paperbacks. each set can be divided equally among the club members. what is the greatest possible number of club members?14 21 147 7
1. C: 15/25>22/44
2. B: 7^5
3. C: -73
4. C: -27
5. A: 344
6. D: 1.34 x 10^1
7. D: 1,070
8. C: 100
9. B: 41
10. B: 6
11. C: 7
12. D: 1/4, 7/16, 5/8, 3/4
13. B: 35/8
14. A: 3 2/3; 11/3
15. B: -0.4, -0.7, -5/16, -9/16
16. D: Amanda
17. B: 0
18. A: 9,180 and 4,932
19. B: 2, 3
20. A: 7/15
21. C: 3 1/3
22. A: 0.36
23 A: 29/100
24 B: 6
The rest are questions you have to answer in your own words. I hope this helped🥱😁!
2. B: 7^5
3. C: -73
4. C: -27
5. A: 344
6. D: 1.34 x 10^1
7. D: 1,070
8. C: 100
9. B: 41
10. B: 6
11. C: 7
12. D: 1/4, 7/16, 5/8, 3/4
13. B: 35/8
14. A: 3 2/3; 11/3
15. B: -0.4, -0.7, -5/16, -9/16
16. D: Amanda
17. B: 0
18. A: 9,180 and 4,932
19. B: 2, 3
20. A: 7/15
21. C: 3 1/3
22. A: 0.36
23 A: 29/100
24 B: 6
The rest are questions you have to answer in your own words. I hope this helped🥱😁!
halp did you take the test and see the answer
Why u asking?
Welp I got to go buh bye
help meh are your answers right
no
WE NEED 2021 ANSWERS
3 answers