The list shows the weight and pounds of six puppies at birth three, 1.6, 2.8, 2.5, 1.7, 2.8 what is the mean absolute deviation of these numbers a 14.4 B 1.9 C 2.4 D 0.5

Answer 1

To find the mean absolute deviation, we first need to calculate the mean of the weights:
(3 + 1.6 + 2.8 + 2.5 + 1.7 + 2.8) / 6 = 2.43 pounds

Next, we calculate the absolute deviations of each weight from the mean:
|3 - 2.43| = 0.57
|1.6 - 2.43| = 0.83
|2.8 - 2.43| = 0.37
|2.5 - 2.43| = 0.07
|1.7 - 2.43| = 0.73
|2.8 - 2.43| = 0.37

Then, we calculate the mean of these absolute deviations:
(0.57 + 0.83 + 0.37 + 0.07 + 0.73 + 0.37) / 6 = 0.52

Therefore, the mean absolute deviation of the weights is 0.52, which is not one of the options provided.