The linear model represents the height, f(x), of a water balloon thrown off the roof of a building over time, x, measured in seconds:
A linear model with ordered pairs at 0, 60 and 2, 75 and 4, 75 and 6, 40 and 8, 20 and 10, 0 and 12, 0 and 14, 0. The x axis is labeled Time in seconds, and the y axis is labeled Height in feet.
Part A: During what interval(s) of the domain is the water balloon's height increasing? (2 points)
Part B: During what interval(s) of the domain is the water balloon's height staying the same? (2 points)
Part C: During what interval(s) of the domain is the water balloon's height decreasing the fastest? Use complete sentences to support your answer. (3 points)
Part D: Use the constraints of the real-world situation to predict the height of the water balloon at 16 seconds. Use complete sentences to support your answer. (3 points)
write this in 4 sentences
5 answers
Part B: The water balloon's height is staying the same during the interval from 2 to 4 seconds. This can be seen in the ordered pair (2, 75) and (4, 75) where the height remains constant at 75 feet.
Part C: The water balloon's height is decreasing the fastest during the interval from 6 to 8 seconds. This conclusion is drawn from the ordered pairs (6, 40) and (8, 20), where the height drops from 40 feet to 20 feet over a span of 2 seconds.
Part D: Based on the linear model, we can predict that the height of the water balloon at 16 seconds will be 0 feet. This prediction is based on the trend observed in the given data: as time increases, the height of the water balloon decreases until it reaches 0 feet at 16 seconds.
x g(x)
1 81
2 83
3 85
Part A: Determine the test average for your math class after completing test 2. (2 points)
Part B: Determine the test average for your science class after completing test 2. (2 points)
Part C: Which class had a higher average after completing test 4? Show work to support your answer. (6 points)
f(2) = 0.5(2) + 80
f(2) = 81
So, the test average for your math class after completing test 2 is 81.
Part B: To determine the test average for your science class after completing test 2, we look at the given information. The average for test 1 is 81, and the average for test 2 is 83. Therefore, the test average for your science class after completing test 2 is 83.
Part C: To determine which class had a higher average after completing test 4, we need to find the test average for each class after completing test 4.
For the math class, we use the same equation f(x) = 0.5x + 80 and plug in x = 4:
f(4) = 0.5(4) + 80
f(4) = 82
For the science class, we need to find the average for test 3 and test 4. According to the given information, the average for test 3 is 85. To find the average for test 4, we assume that the trend continues with a constant increase of 2.
Test 4 average = Test 3 average + increase
Test 4 average = 85 + 2
Test 4 average = 87
Comparing the averages, we can see that the math class had an average of 82 after completing test 4, while the science class had an average of 87 after completing test 4. Therefore, the science class had a higher average after completing test 4.
x g(x)
0 $1,500
2 $1,350
4 $1,200
Part A: Find and interpret the slope of the function. (3 points)
Part B: Write the equation of the line in point-slope, slope-intercept, and standard forms. (3 points)
Part C: Write the equation of the line using function notation. (2 points)
Part D: What is the balance in the bank account after 5 days? (2 points)
Using the values from the table, we can calculate the change in y and the change in x:
(change in y) = $1,200 - $1,500 = -$300
(change in x) = 4 - 0 = 4
Now we can calculate the slope:
slope = (-$300)/(4) = -$75
Interpretation: The slope of the function is -$75, which means that for every increase of 1 in the number of days, the balance in the bank account decreases by $75.
Part B:
Point-slope form: We can use the point-slope form of a linear equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
Using the point (0, $1,500) and the slope -$75, the equation in point-slope form is:
g(x) - $1,500 = -$75(x - 0)
Slope-intercept form: The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.
Substituting the values of the slope and the y-intercept (from the point (0, $1,500)) into the equation:
g(x) = -$75x + $1,500
Standard form: The standard form of a linear equation is Ax + By = C, where A, B, and C are constants.
Converting the equation from slope-intercept form to standard form:
$75x + g(x) = $1,500
Part C: Using function notation, the equation of the line can be written as:
g(x) = -$75x + $1,500
Part D: To find the balance in the bank account after 5 days, we can substitute x = 5 into the equation:
g(5) = -$75(5) + $1,500 = $1,125
Therefore, the balance in the bank account after 5 days is $1,125.