The linear function y=1/2x−5 is graphed on the same axis as the quadratic function. Enter the coordinates of the solution with a positive x-coordinate. (1 point) The coordinates of the solution with a positive x-value are (,).

1 answer

To find the coordinates of the solution where the linear function \( y = \frac{1}{2}x - 5 \) intersects with a quadratic function, we first need to know the equation of the quadratic function. Since you didn't provide the equation, I'll represent it generally as \( y = ax^2 + bx + c \).

To determine the points of intersection, we set the two equations equal to each other:

\[ \frac{1}{2}x - 5 = ax^2 + bx + c \]

Rearranging this equation leads us to:

\[ ax^2 + (b - \frac{1}{2})x + (c + 5) = 0 \]

You would then solve this quadratic equation for \( x \) using the quadratic formula:

\[ x = \frac{-(b - \frac{1}{2}) \pm \sqrt{(b - \frac{1}{2})^2 - 4a(c + 5)}}{2a} \]

From the solutions for \( x \), you would identify the one with the positive value.

If you provide the specific quadratic function, I can give you a more exact answer or calculate it directly.