To determine which statements are true regarding the linear equation representing the average cost of a loaf of white bread since 1985, we need to analyze the given coordinates and the proposed linear equation.
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Finding the linear equation: Given points are:
- (10, 0.85), which represents the year 1995 (10 years after 1985)
- (17, 1.06), which represents the year 2002 (17 years after 1985)
- (23, 1.24), which represents the year 2008 (23 years after 1985)
- (30, 1.45), which represents the year 2015 (30 years after 1985)
To find the slope (m) of the line connecting any two points, we can use the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Let's take the points (10, 0.85) and (30, 1.45): \[ m = \frac{1.45 - 0.85}{30 - 10} = \frac{0.60}{20} = 0.03 \]
Now we can find the y-intercept (b) using the equation of a line \(y = mx + b\). Using the point (10, 0.85): \[ 0.85 = 0.03(10) + b \implies 0.85 = 0.30 + b \implies b = 0.55 \] Therefore, the equation of the line is: \[ y = 0.03x + 0.55 \]
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Evaluating each statement:
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y = 0.03x + 0.55 represents the linear equation.
- True (confirmed by our calculation)
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The cost of a loaf of bread in 1990 was $0.70.
- 1990 corresponds to \(x = 5\): \[ y = 0.03(5) + 0.55 = 0.15 + 0.55 = 0.70 \]
- True
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(27, 1.48) is a solution to the linear equation.
- Plugging \(x = 27\): \[ y = 0.03(27) + 0.55 = 0.81 + 0.55 = 1.36 \]
- Since \(1.48 \neq 1.36\), this statement is False.
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The cost of a loaf of bread in 2015 was $1.50.
- 2015 corresponds to \(x = 30\): \[ y = 0.03(30) + 0.55 = 0.90 + 0.55 = 1.45 \]
- Since $1.50 does not equal $1.45, this statement is False.
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(5, 0.7) is a solution to the linear equation.
- Plugging \(x = 5\): \[ y = 0.03(5) + 0.55 = 0.70 \]
- True
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A loaf of bread cost $0.55 in 1985.
- The year 1985 corresponds to \(x = 0\): \[ y = 0.03(0) + 0.55 = 0.55 \]
- True
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In conclusion, the true statements are:
- y = 0.03x + 0.55 represents the linear equation.
- The cost of a loaf of bread in 1990 was $0.70.
- (5, 0.7) is a solution to the linear equation.
- A loaf of bread cost $0.55 in 1985.