The linear approximation at x=0 to f(x)= sqrt (7+6x) is y=

1 answer

for f(x)=sqrt(7+6x)
Calculate the slope at x0=0, i.e.
m=f'(x0)=f'(0)
and the value of y0=f(x0) to give the tangent point (x0, f(x0))=(0,f(0))

The linear approximation at x=0 is given by
y = m(x-x0)+y0
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