y=sqrt x
y'=1/(2sqrtx)
but y=2x+b, slope is 2, so
2=1/(2sqrtx)
sqrt x=1/4
x=+ 1/2
solve for y.
The line y=2x+b is tangent to the graph of y=x^1/2 at the point P=(a, a^1/2). Find P and determine b.
I don't know what to do because they don't give you the x coordinate or anything to plug into the derivative. Help?
2 answers
thank you soo much!