slope of line Q = (-8+2)/(-8+10) = -6/2 = -3
slope of line R = (a-2)/(10-1) = (a-2)/9
but they are perpendicular, so
(a-2)/9 = -1/3
continue
The line Q passes through the points (-10,-2) and (-8,-8).
The line R passes through the points (1,2) and (10,a).
The lines Q and R are perpendicular.
Find a.
Thanks.
1 answer