the line perpendicular to 4y-2x=7/3 passing through (9, -2) write an equation for each line described express answer in point slope or slope intercept.

Answer 1

4 y = 2 x - 7/3
y = (1/2) x = 7/6
slope = 1/2
slope of perpendicular = -1/(1/2)
= -2
so we want
y = -2 x + b
plug point in to get b
-2 = -2(9) + b
b = 16
y = -2 x + 16

Answer 2

will you please explain it more

Answer 3

ok
I put the original line in the form
y = m x + b
then m, the slope was 1/2

m' the slope of a perpendicular = -1/m
so m' = -1/(1/2) = -2

so I know the line I am looking for is of form
y = -2 x + b
but I do not know b
so I put the x and y in for a point on that line and from that I can get b

Answer 4

You know that perpendicular lines have slopes that are negative reciprocals of each other.

Thus the new perpendicular line is
4x+2y= c
plug in your pont (9,-2)
36 - 4 = c = 32

4x + 2y = 32
2x + y = 16