gradient
= slope
= (6-(-2))/(6-0)
= 8/6 = 4/3
since (0,-2) is the y-intercept or the b of the y = mx + b notation, we can simply write
y = (4/3) - 2
surely you have 2 little formulas in your text or your notebook to find the midpoint and the length.
Let me know what you get.
the line passes through the points s(6,6) and T(0,-2) determine the gradient of the line
the equation of the line
the midpoint of the line segment,TS
the length of the line segment,TS
3 answers
mid point
y2+y1/2
-2+6/2
4/2
=2
x2-x1/2
0-6/2
-6/2
=-3
y2+y1/2
-2+6/2
4/2
=2
x2-x1/2
0-6/2
-6/2
=-3
Ohh dear!
midpoint is a "point" so it must look like ( ? , ? )
your method should be
the x of the midpoint is (6+0)/2= 3
the y of the midpoint is (6-2)/2 = 2
so the midpoint is (3,2)
(notice that in effect we are taking the average of the x's and the average of the y's)
length
= √(6-0)^2 + (6-(-2))^2)
= √(36 +64)
= √100
= 10
midpoint is a "point" so it must look like ( ? , ? )
your method should be
the x of the midpoint is (6+0)/2= 3
the y of the midpoint is (6-2)/2 = 2
so the midpoint is (3,2)
(notice that in effect we are taking the average of the x's and the average of the y's)
length
= √(6-0)^2 + (6-(-2))^2)
= √(36 +64)
= √100
= 10