740747 cm-1, 877924 cm-1, 925933
The shortest wavlength should express a transition from level 2 to level1
1/lambda=C(1/n2^2-1/n1^2) Where C is some constant.
for n2=2, n1=1 then
1/lambda1=C(3/4)
or C=4/(3*lambda1)
lets look at the next transition:
1/lambda2=C(1/9-1/1) or
C=9/(8lambda2)
well, if C is truly a constant, these constants must match (and you can do it for the third also)
does 4/ (3lambda1)=9/8(lambda2)
or does lambda1/lambda2=24/27=.843
740747/877924 =.843 Ah Ha.
so explore this for lambda 3. Then work on what is the constant . Watch constants in h, c, and R
The Li2+ ion is hydrogenic and has a Lyman series at 740747 cm-1, 877924 cm-1, 925933 cm-1,and beyond. Show that the energy levels are of the form –hcR/n^2 and find the value of R for this ion. Go on and predict the wavenumbers of the two longest wavelength transitions of the Balmer series of the ion and find the ionization energy of
the ion.
2 answers
Make certain you understand wavenumber vs wavelength. It does not change the ratio obtained in the above (just inverse).
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