The letter tiles S, M, I, L, E are placed on a box. Without looking, James picks a letter tile from the box. Which model represents the possible outcomes of James’ experiment?(1 point) Responses Image with alt text: A bar chart is titled Probability of Picking a Letter from the Word SMILE. The chart is plotted for outcomes on the x-axis against probability on the y-axis. The x-axis shows bars for the individual letters S, M, I, L, and E. The y-axis for probability ranges from 0 to 0.25 in increments of 0.05. The probability of each of the letters S, M, I, L, and E is approximately 0.20. Image with alt text: A bar chart is titled Probability of Picking a Letter from the Word SMILE. The chart is plotted for outcomes on the x-axis against probability on the y-axis. The x-axis shows bars for the individual letters S, M, I, L, and E. The y-axis for probability ranges from 0 to 0.35 in increments of 0.05. The probability of each of the letters is as follows: S is 0.15, M is 0.20, I is 0.30, L is 0.20, and E is 0.15. Image with alt text: A bar chart is titled Probability of Picking a Letter from the Word SMILE. The chart is plotted for outcomes on the x-axis against probability on the y-axis. The x-axis shows bars for the individual letters M, I, L, and E. The y-axis for probability ranges from 0 to 1.2 in increments of 0.2. The probability of each of the letters M, I, L, and E is 1 percent. Image with alt text: A bar chart is titled Probability of Picking a Letter from the Word SMILE. The chart is plotted for outcomes on the x-axis against probability on the y-axis. The x-axis shows bars for the individual letters M, I, L and E. The y-axis for probability ranges from 0 percent to 25 percent in increments of 5 percent. The probability of each of the letters M, I, L and E is 20 percent. Skip to navigation
1 answer
The model that represents the possible outcomes of James' experiment is the first one. The bar chart shows the probability of picking each letter (S, M, I, L, E) from the word SMILE, with each letter having an approximate probability of 0.20.