To classify the triangle with sides of lengths 7, 5, and 8, we can use the relationships defined by the Pythagorean theorem.
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Calculate the squares of the sides:
- \( a^2 = 7^2 = 49 \)
- \( b^2 = 5^2 = 25 \)
- \( c^2 = 8^2 = 64 \)
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Determine the relationship among the squares:
- Arrange the sides such that \( c \) is the longest side. Here, \( c = 8 \), \( a = 7 \), and \( b = 5 \).
- Evaluate \( a^2 + b^2 \) and compare it to \( c^2 \):
- \( a^2 + b^2 = 49 + 25 = 74 \)
- \( c^2 = 64 \)
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Compare \( a^2 + b^2 \) to \( c^2 \):
- Since \( 74 > 64 \), we have \( a^2 + b^2 > c^2 \).
Given the relationship, we can conclude:
- If \( a^2 + b^2 > c^2 \), the triangle is acute.
- If \( a^2 + b^2 = c^2 \), the triangle is right.
- If \( a^2 + b^2 < c^2 \), the triangle is obtuse.
Since \( a^2 + b^2 > c^2 \), the triangle with sides 7, 5, and 8 is classified as acute.