The length, width, and height of a cube are all labeled a.

A cube has an edge length, a
, that is a rational number of centimeters. Identify which measurement will require the use of irrational numbers.

(1 point)
Responses

the volume of the cube
the volume of the cube

the diagonal of one of the cube’s faces
the diagonal of one of the cube’s faces

the surface area of the cube
the surface area of the cube

the area of one of the cube’s faces

1 answer

To determine which measurement will require the use of irrational numbers, let's analyze each option:

  1. The volume of the cube: The volume \( V \) of a cube with edge length \( a \) is calculated using the formula \( V = a^3 \). Since \( a \) is a rational number, the volume will also be a rational number.

  2. The diagonal of one of the cube’s faces: The diagonal \( d \) of one of the cube's faces (which is a square) can be found using the Pythagorean theorem. If the edge length is \( a \), the diagonal is given by \( d = \sqrt{a^2 + a^2} = \sqrt{2a^2} = a\sqrt{2} \). Since \( \sqrt{2} \) is an irrational number, the diagonal will be irrational if \( a \) is not zero.

  3. The surface area of the cube: The surface area \( S \) of a cube is calculated using the formula \( S = 6a^2 \). As long as \( a \) is rational, the surface area will also be rational.

  4. The area of one of the cube’s faces: The area \( A \) of one face of the cube is \( A = a^2 \). Since \( a \) is rational, the area will be rational.

Based on this analysis, the measurement that requires the use of irrational numbers is:

The diagonal of one of the cube’s faces.