I have just answered 5 of your previous 6 questions.
You have shown no sign of any effort on your part.
Mmmhh, I wonder what makes me think that I am doing your assignment for you ?
Until I see some effort shown on your part, or some indication where your difficulties lie, .... no more replies from me.
The length of two pendulum is 110 cm and 27.5 cm, calculate the ration of their time periods
2 answers
T1 = 2π√27.5/√g
T1^2 = 4π^27.5g
T2 = 2π√27.5/√g
T2^2 = 4π^110g
T1^2/T2^2 = 4π^27.5g/4π^110g
T1^2/T2^2 = 27.5/110 = 275/1100 = 1/4
T1/T2 = √(1/4)
so T1: T2 = 1 : 2
T1^2 = 4π^27.5g
T2 = 2π√27.5/√g
T2^2 = 4π^110g
T1^2/T2^2 = 4π^27.5g/4π^110g
T1^2/T2^2 = 27.5/110 = 275/1100 = 1/4
T1/T2 = √(1/4)
so T1: T2 = 1 : 2
0 answers