Asked by manavi
The length of two pendulum is 110 cm and 27.5 cm, calculate the ration of their time periods
Answers
Answered by
Reiny
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You have shown no sign of any effort on your part.
Mmmhh, I wonder what makes me think that I am doing your assignment for you ?
Until I see some effort shown on your part, or some indication where your difficulties lie, .... no more replies from me.
Answered by
S
T1 = 2π√27.5/√g
T1^2 = 4π^27.5g
T2 = 2π√27.5/√g
T2^2 = 4π^110g
T1^2/T2^2 = 4π^27.5g/4π^110g
T1^2/T2^2 = 27.5/110 = 275/1100 = 1/4
T1/T2 = √(1/4)
so T1: T2 = 1 : 2
T1^2 = 4π^27.5g
T2 = 2π√27.5/√g
T2^2 = 4π^110g
T1^2/T2^2 = 4π^27.5g/4π^110g
T1^2/T2^2 = 27.5/110 = 275/1100 = 1/4
T1/T2 = √(1/4)
so T1: T2 = 1 : 2
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