a=2/3b
3a = 2b
b = 3a/2
c=3/2b
2c = 3b
b = 2c/3
thus: 2c/3 = 3a/2
4c = 9a
4/9 = a/c
a : c = 4 : 9
notice 2/3b ≠ 2/(3b)
I assumed you meant it the way you typed it.
The length of three line segments are a,b, and c respectively,
and a=2/3b c=3/2b then a : c = ?
5 answers
a:b = 2:3
c:b = 3:2
we want b in the middle, so
b:c = 2:3
lcm(2,3) = 6, so now we can write
a:b = 4:6
b:c = 6:9
a:b:c = 4:6:9
a:c = 4:9
c:b = 3:2
we want b in the middle, so
b:c = 2:3
lcm(2,3) = 6, so now we can write
a:b = 4:6
b:c = 6:9
a:b:c = 4:6:9
a:c = 4:9
can you explain to me what you mean when you said you need "b" in the middle? thanks
b is bigger than a and smaller than c
it's not that b is the middle value, but that if we want to build a set of ratios,
a:b:c
we need to have a common value for b in the two ratios
a:b and b:c
We could not have placed a or c in the center spot, because we only had one ratio for each of those. But to join the two ratios, we need a single value for b.
a:b:c
we need to have a common value for b in the two ratios
a:b and b:c
We could not have placed a or c in the center spot, because we only had one ratio for each of those. But to join the two ratios, we need a single value for b.
1 answer