The length of the shadow of a pole on the level ground increases by 60 meter when one angle of elevation of the sun changes 54° to 32°.calaulate the height of the pole,correct to three significants figures.

Answer 1

over in the triangle between shadows we have a 32 degree angle. At the other end of our 60 meters we have a 180=54 = 126 degree angle. Therfore up at the top of that triangle we have a 180 - 32 - 126 = 22 degree angle
law of sines for long hypotenuse ray call it x
sin 126/x = sin 22/60
x = 60 sin 126/sin 22 = 130 meters
so
sin 32 = h /130
h = 68.7 meters high

Answer 2

Good
But no diagram