The length of the hypotenuse (x) is an irrational number between 6 and 8. Both legs have measures that are whole numbers. Illustrate a model for at least one possible set of measures for the sides of the right triangle.
8 answers
4^2 + 5^2 = 41
omg so thats the formula?
Tytytyty
Can you please explain
just try
hypotenuse squared between
x^2+y^2 = 36
to
x^2 + y^2 = 64
for example try 3 and something
3^2 + 7^2 = 58, that works sqrt 58 = 7.615 ..... etc
hypotenuse squared between
x^2+y^2 = 36
to
x^2 + y^2 = 64
for example try 3 and something
3^2 + 7^2 = 58, that works sqrt 58 = 7.615 ..... etc
I still dont understand so i try a number between 7 and 8 to try and find the other ones?
I dont want the answer i wanna learn how to do it so I don't have to depend on other people
the square of the hypotenuse is between 36 and 64 ... 6^2 and 8^2
from Pythagoras ... a^2 + b^2 = c^2
so the sum of the squares of the two legs is more than 36 and less than 64
you are looking for pairs of whole numbers with the correct sum of squares
... as the question indicates , there are multiple possibilities
from Pythagoras ... a^2 + b^2 = c^2
so the sum of the squares of the two legs is more than 36 and less than 64
you are looking for pairs of whole numbers with the correct sum of squares
... as the question indicates , there are multiple possibilities