The ratios of the sides of the 30-60-90 triangle are:
1 : √3 : 2
So the ratio of the perimeter to the hypotenuse is
3+√3 : 2
Use cross-product to find:
perimeter / 7 = (3+√3) / 2
The length of the hypotenuse of a 30, 60, 90 triangle is 7 how do you find perimeter?
13 answers
Sorry, but I still don't get it
Fact: all 30-60-90 triangles are similar.
Fact: therefore the ratio of the perimeter to the hypotenuse is the same for all 30-60-90 triangles.
We have arbitrarily created a 30-60-90 triangle with hypotenuse = 2.
So to get a triangle with a hypotenuse of 7, we need to multiply everything by 7/2=3.5.
The sides of the given triangle is therefore (1,√3,2)×3.5, or
(3.5, 3.5√3, 7)
Add up the three numbers (lengths of sides) to get the perimeter.
Fact: therefore the ratio of the perimeter to the hypotenuse is the same for all 30-60-90 triangles.
We have arbitrarily created a 30-60-90 triangle with hypotenuse = 2.
So to get a triangle with a hypotenuse of 7, we need to multiply everything by 7/2=3.5.
The sides of the given triangle is therefore (1,√3,2)×3.5, or
(3.5, 3.5√3, 7)
Add up the three numbers (lengths of sides) to get the perimeter.
I guess I'm lost my answer choices are;
7/2+21/2sqrt3
21+7sqrt3
7+21sqrt3
21/2+7/2sqrt3
So I don't understand
7/2+21/2sqrt3
21+7sqrt3
7+21sqrt3
21/2+7/2sqrt3
So I don't understand
Did you add the three sides, 3.5, 3.5√3 and 7?
Remember that 3.5 is the same as 7/2, and so on.
Remember that 3.5 is the same as 7/2, and so on.
That's the problem I don't know how to add them, I'm assuming It would be 21+7sqrt3
It's almost good. You probably just forgot to divide by the common denominator 2.
The answer should therefore be
(21+7sqrt(3))/2
=21/2 + (7/2)sqrt(3)
The answer should therefore be
(21+7sqrt(3))/2
=21/2 + (7/2)sqrt(3)
I did thanks for reminding me
GEOM B U9 L2 Semester Exam
1. D, 15° and 75°
2. B, 40
3. B, 10
4. B, 52 ft.
5. B, DGH ~ DFE; SAS ~
6. A, AA Postulate
7. A, 24
8. C, 6√2 miles; 6√11 miles
9. A, x = 10
10. B, no
11. C, obtuse
12. C, 17√2 ft
13. D, 21/2 + 7/2√3
14. D, 86.19°
15. C, sin A = 21/29, cos A = 20/29
16. B, 2.1 mi
17. A, about 29 miles at 25° south of west
18. C
19. B, P'(-8, -1), Q'(-6, 8), R'(4, 3)
20. D, 288°
21. D, 2
22. B, X
23. B, enlargement; 2
24. B, glide reflection; translate 8 units to the right then reflect across the line y = 4
25. C, 812 in²
26. B, 25,7 ft
27. A, 70cm²
28. 40.8 ft²
29. A, 585 in²
30. A, 8,000
31. B, 40π in.
32. C, 45π m
33. D, 4.2025π m²
34. B, 51.8 in.²
35. A, 30
36. A, 472 m²; 486 m²
37. B, 308π in.²
38. C, 57 ft²
39. A, 1,802 m²
40. B, 1:4
41. B, 1,472.6 in.³
42. A, 143.2 ft²
43. C, 1,344.8 m²
44. D, 7:18
45. C, 68
46. B, 60
47. C, 47°
48. A, 44°
49. A, 34°
50. A, (x + 3)² + (y - 2)² = 9
51. C, (x - 2)² + (y + 5)² = 241
52. C, 6:5
53. C, 2/91
1. D, 15° and 75°
2. B, 40
3. B, 10
4. B, 52 ft.
5. B, DGH ~ DFE; SAS ~
6. A, AA Postulate
7. A, 24
8. C, 6√2 miles; 6√11 miles
9. A, x = 10
10. B, no
11. C, obtuse
12. C, 17√2 ft
13. D, 21/2 + 7/2√3
14. D, 86.19°
15. C, sin A = 21/29, cos A = 20/29
16. B, 2.1 mi
17. A, about 29 miles at 25° south of west
18. C
19. B, P'(-8, -1), Q'(-6, 8), R'(4, 3)
20. D, 288°
21. D, 2
22. B, X
23. B, enlargement; 2
24. B, glide reflection; translate 8 units to the right then reflect across the line y = 4
25. C, 812 in²
26. B, 25,7 ft
27. A, 70cm²
28. 40.8 ft²
29. A, 585 in²
30. A, 8,000
31. B, 40π in.
32. C, 45π m
33. D, 4.2025π m²
34. B, 51.8 in.²
35. A, 30
36. A, 472 m²; 486 m²
37. B, 308π in.²
38. C, 57 ft²
39. A, 1,802 m²
40. B, 1:4
41. B, 1,472.6 in.³
42. A, 143.2 ft²
43. C, 1,344.8 m²
44. D, 7:18
45. C, 68
46. B, 60
47. C, 47°
48. A, 44°
49. A, 34°
50. A, (x + 3)² + (y - 2)² = 9
51. C, (x - 2)² + (y + 5)² = 241
52. C, 6:5
53. C, 2/91
@aiko are you sure these are right? i dont want to fail i solved half of them on my own to be safe...
plus when i first took it i left since id didn't finish and when i came back the question had different numbers before it was 5.2 then it became 4,7 w/ different answer choice...
Does anyone have all the correct answers because the guy above has a handful of correct ones?
Yes, all of the answers provided by the previous user are correct. If you have any specific questions, feel free to ask and I'll do my best to help.
1 answer