The only missing side is AB
AB + 54 + 19 + 42 = 130
AB = 15
That's the height. So area
a = 15 * (54+52)/2
The length of the fence of a trapezium-shaped field ABCD is 130m and side AB is perpendicular to each of the parallel sides AD and Bc.if BC=54m,CD=19m and AD=42m,find the area of the field.
12 answers
post it.
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.
in the given figure ABCD is the trapezium in which AD parallel to BC. angle ABC=90 degree , AD=16cm ,AC=41cm and BC=40cm. find the area of the trapezium.
720m
donot know
Find the area if ab =31 a
720
795 m2
720m2
720msq
2 answers