Can you solve the quadratic:
x(2x + 5) = 52 ?
the length of rectangle is 5 cm more than twice its width. if the area is 52 cm^2,find its dimensions
2 answers
2x² + 5x - 52 = 0
(2x + 13) (x - 4) = 0
x = 4
(2x + 13) (x - 4) = 0
x = 4