The length of a swimming pool is 23 units more than its width.if the area is 420 sq.units, what are their dimensions?

1 answer

L = W + 23

L * W = 420 ... (W + 23) * W = 420 ... W^2 + 23 W - 420 = 0

(W + 35) (W - 12) = 0

W = 12