Let's assume the length of the square is L.
If the length increases by 20%, then the new length is 1.2L.
The area of a square is given by A = L^2.
Therefore, the new area is (1.2L)^2 = 1.44L^2.
The increase in the area is given by (1.44L^2 - L^2)/L^2 = 0.44.
To express this increase as a percentage, we multiply by 100% to get 0.44 * 100% = 44%.
Therefore, the area of the square increases by 44%.
the length of a square increases by 20%. By what percentage does the area of the square increase?
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