the length of a square increases by 20%. By what percentage does the area of the square increase?

1 answer

Let's assume the length of the square is L.

If the length increases by 20%, then the new length is 1.2L.

The area of a square is given by A = L^2.

Therefore, the new area is (1.2L)^2 = 1.44L^2.

The increase in the area is given by (1.44L^2 - L^2)/L^2 = 0.44.

To express this increase as a percentage, we multiply by 100% to get 0.44 * 100% = 44%.

Therefore, the area of the square increases by 44%.