The length of a spring increases by 7.2 cm from its relaxed length when a mass of 1.4 kg is hanging in equilibrium from the spring. (a) What is the spring constant? (b) How much elastic potential energy is stored in the spring? (c) A different mass is suspended and the spring length increases by 12.2 cm from its relaxed length to its new equilibrium position. What is the second mass?

Answer 1

Work is indeed needed. Why don't you show any?

The definition of spring constant (k) is force divided by deflection.

Elastic energy is (1/2)kX^2

Deflection is proportional to mass.

If you are not going to attempt problems like this, you are not going to learn physics.

Answer 2

ok ka lang?