Let "L"= length
Let "W"= width
2L+2W= 52
3W-2= L
substitute in for "L"
2(3W-2)+2W=52
distribute/add
8W-4=52
isolate variable
56=8W
divide
w=7
2L+14=52
2L=38
L=19
The length of a rectangular piece of steel in a bridge is 2 meters less than triple the width. The perimeter of the piece of steel is 52 meters. Find the length of the piece of steel. Find the width of the piece of steel
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