Asked by David
the length of a rectangular garden exceeds its width by 8 feet. if each side of the garden is increased by 2 feet, the area of the garden will be increased by 60 square feet. find the dimensions of the original garden
Answers
Answered by
Reiny
original:
width -- x
length -- x+8
area = x(x+8)
new width = x+2
new length = x+10
new area = (x+2)(x+10)
(x+2)(x+10) - x(x+8) = 60
x^2 + 12x + 20 - x^2 - 8x = 60
2x = 40
x = 10
original garden is 10 ft by 18 ft
check:
original area = 10(18) = 180
new area = 12(20) = 240
increase in area = 240-180 = 60
all looks good.
width -- x
length -- x+8
area = x(x+8)
new width = x+2
new length = x+10
new area = (x+2)(x+10)
(x+2)(x+10) - x(x+8) = 60
x^2 + 12x + 20 - x^2 - 8x = 60
2x = 40
x = 10
original garden is 10 ft by 18 ft
check:
original area = 10(18) = 180
new area = 12(20) = 240
increase in area = 240-180 = 60
all looks good.
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