The length of a rectangle is twice it width if the width is reduced by 1cm, and the length is reduced by 2cm, the area will be 15cm². Find the dimensions of the original rectangle

Answer 1

if the width is w, then we have
(w-1)(2w-2) = 15
2(w-1)^2 = 15
(w-1)^2 = 15/2
Now finish it off. Not a nice rational answer ...
It's a little better if the area is reduced by 15 cm^2, but still not an integer.