length is 3/2
so, width is 2/3
The length of a rectangle is increased by 50%. By what percent would the width be increased to keep the same area?
a.43/3
b.45/4
c.33-1/3
d.31-1/3
5 answers
sorry but i don't get it
so, if the dimensions are x and y,
50% increase of y is 1.5y. But, you want the new area to be the same. So, if x is multiplied by k, you want
(k)(x)(3/2)(y) = xy
(k)(3/2)(xy) = xy
k(3/2) = 1
k = 2/3
So, if the new width is 2/3 of the old width, that is a decrease of 1/3, or 33-1/3 %
50% increase of y is 1.5y. But, you want the new area to be the same. So, if x is multiplied by k, you want
(k)(x)(3/2)(y) = xy
(k)(3/2)(xy) = xy
k(3/2) = 1
k = 2/3
So, if the new width is 2/3 of the old width, that is a decrease of 1/3, or 33-1/3 %
what is k by the way?
do you actually read what I write? I explained k, and I used it. Don't make me do your thinking as well as your math!