The length of a rectangle is four times its width. If the perimeter of the rectangle is ,70m find its length and width.

Answer 1

To find the length and width of the rectangle, we can use the information provided:

1. Let the width of the rectangle be \( w \).

2. Then, the length \( l \) of the rectangle is four times the width: \[ l = 4w \]

3. The formula for the perimeter \( P \) of a rectangle is given by: \[ P = 2l + 2w \]

4. We are told the perimeter is 70 m, so we set up the equation: \[ 2l + 2w = 70 \]

5. Substitute \( l \) with \( 4w \) in the perimeter equation: \[ 2(4w) + 2w = 70 \] \[ 8w + 2w = 70 \] \[ 10w = 70 \] \[ w = 7 \]

6. Now, substitute \( w \) back to find the length: \[ l = 4w = 4 \times 7 = 28 \]

Thus, the width of the rectangle is \( 7 \) m and the length is \( 28 \) m.

Final Answer: Width = 7 m, Length = 28 m.