The length of a rectangle is four times its width. If the perimeter of the rectangle is 80ft find its area

Answer 1

Let the width of the rectangle be x ft.

Then the length of the rectangle is 4x ft.

Perimeter of the rectangle = 2(length + width)
= 2(4x + x)
= 2(5x)
= 10x

Given that the perimeter is 80 ft, we have:
10x = 80
x = 8

Therefore, the width of the rectangle is 8 ft and the length is 4(8) = 32 ft.

Area of the rectangle = length x width
= 32 x 8
= 256 sq ft

Therefore, the area of the rectangle is 256 sq ft.