\(length = 2w - 4\) (since the length is four meters less than twice its width)
\(area = length \times width = (2w - 4) \times w = 96\)
\(2w^2 - 4w = 96\)
\(2w^2 - 4w - 96 = 0\)
Using trial and error to solve this quadratic equation, we find that the width is 8 meters and the length is 12 meters. Thus, the length is 12 meters and the width is 8 meters.
The length of a rectangle is four meters less than twice its width..
If the area of the rectangle is 96 m^2, what is the length and the width?
An expression for the length of the rectangle in terms of the width would be Response area
The formula for the area of a rectangle is Response area
Using trial and error, if the area is 96 m^2, then the length and width are
1 answer
1 answer