To express the length of the rectangle in terms of its width, we can use the information given:
Let the width be denoted as \( w \).
According to the problem, the length \( l \) of the rectangle is four meters less than twice its width. This relationship can be expressed mathematically as:
\[ l = 2w - 4 \]
So, the expression for the length of the rectangle in terms of the width is:
2w - 4.
Next, we can use the area of the rectangle to find the values of width and length. The area \( A \) of a rectangle is given by the formula:
\[ A = l \times w \]
We know the area is 96 m², so:
\[ 96 = (2w - 4) \times w \]
Expanding this equation gives:
\[ 96 = 2w^2 - 4w \]
Rearranging to set the equation to zero:
\[ 2w^2 - 4w - 96 = 0 \]
Dividing the entire equation by 2 simplifies it:
\[ w^2 - 2w - 48 = 0 \]
Now, we can factor this quadratic equation:
\[ (w - 8)(w + 6) = 0 \]
Setting each factor to zero gives:
- \( w - 8 = 0 \) → \( w = 8 \)
- \( w + 6 = 0 \) → \( w = -6 \) (not a valid solution since width can't be negative)
Thus, the width \( w \) is 8 m.
Now, substitute back to find the length:
\[ l = 2(8) - 4 = 16 - 4 = 12 \]
So, the dimensions of the rectangle are:
Width = 8 m Length = 12 m