Q1. A wire of length 200 cm is cut into two parts and each part is bent to form a square. If the area of the larger square is 9 times that of the smaller square, find the perimeter of the larger square.
Q2. A wire of length 100cm is cut into two parts and each part is bent to form a square. If the sum of the areas of the two squares is 425cm^2, find the lengths of the sides of the two squares.
Q3. A group of students is on a sightseeing tour. the total fare is $120 and this is to be shared equally among the students. If two more students join the tour, each will pay $2 less. Find the original number of students in the group
the length of a rectangle is 8cm more than the width and its area is 172cm^2 .Find
a) the width od the rectangle;
b) the length of the diagonal of the rectangle, giving your answer correct to 2 decimal places
3 answers
w(w+8) = 172
w = 2(√47 - 2)
Now you can get the other values.
Q1 since the larger is 9 times the area, it has 3 times the perimeter. So, the two squares have perimeters 50 and 150.
Q2
x^2 + y^2 =425
4x+4y = 100
The squares have sides 5 and 20
Q3
If there are x students paying $y each, then
xy = 120
(x+2)(y-2) = 120
By inspection, x=10,y=12
w = 2(√47 - 2)
Now you can get the other values.
Q1 since the larger is 9 times the area, it has 3 times the perimeter. So, the two squares have perimeters 50 and 150.
Q2
x^2 + y^2 =425
4x+4y = 100
The squares have sides 5 and 20
Q3
If there are x students paying $y each, then
xy = 120
(x+2)(y-2) = 120
By inspection, x=10,y=12
I agree with steve
0 answers