L = w + 8
(L-5 )(w+4) = L w
(w+8-5)(w+4) = (w+8)w
(w+3)(w+4) = w^2 + 8 w
w^2 + 7 w + 12 = w^2 + 8 w
w = 12 etc
The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 feet, the area will remain the same. Find the dimensions of the original rectangle.
1 answer