The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 feet, the area will remain the same. Find the dimensions of the original rectangle.

1 answer

L = w + 8

(L-5 )(w+4) = L w

(w+8-5)(w+4) = (w+8)w

(w+3)(w+4) = w^2 + 8 w

w^2 + 7 w + 12 = w^2 + 8 w

w = 12 etc