the length of a rectangle is 6 cm more than its width. the area is 11 cm squared. find the length and width.
look at the post by anonymous at 8:55, it is almost the same as yours.
Do it the same way.
length= x+6
width=x
x(x+6)=11
x^2 + ^x =11
x^2+6x-11=0
(x-_)(x-_)
solve for x.
Then substute the x for the length and width.
2 answers
l=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X-11=0
l=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X-11=0, I GOT - 43 AND 43 BY AX2+BX+C=0