The length of a rectangle is 5ft longer than twice the width. If the perimeter is 106ft, find the length and the width of the rectangle.

Answer 1

P = 2L + 2W

106 = 2(W + 5) + 2W

106 = 4W + 10

96 = 4W

24 = width

Answer 2

What we know:

Length = 2X + 5
Width = X

Perimeter = 2L + 2W
106 = 2(2X + 5) + 2X
106 = 4X + 10 + 2X
106 - 10 = 6X
96 = 6X

96 = 6X
___ ___
6 6

16 = X

Now we know X is 16 (Width)

Let's substitute:

Width = 16
Length = 2X + 5
= 2(16) + 5
= 37

Double check answers:

Perimeter = 2L + 2W
106 = 2(37) + 2(16)
106 = 74 + 32